(Created page with "== Metric Trees == Metric tree in an indexing structure that allows for efficient KNN search Metric tree organizes a set of points hierarchically...")
(No difference)

Latest revision as of 22:58, 27 April 2017

Metric Trees

Metric tree in an indexing structure that allows for efficient KNN search

Metric tree organizes a set of points hierarchically

  • It's a binary tree: nodes = sets of points, root = all points
  • sets across siblings (nodes on the same level) are all disjoint
  • at each internal node all points are partitioned into 2 disjoint sets


  • let $N(v)$ be all points at node $v$
  • $\text{left}(v), \text{right}(v)$ - left and right children of $v$

Splitting a node:

  • choose two pivot points $p_l$ and $p_r$ from $N(v)$
  • ideally these points should be selected s.t. the distance between them is largest:
    • $(p_l, p_r) = \operatorname{arg max}\limits_{p_1, p_2 \in N(v)} \| p_1 - p_2 \|$
    • but it takes $O(n^2)$ (where $n = |N(v)|$) to find optimal $p_l, p_r$
  • heuristic:
    • pick a random point $p \in N(v)$
    • then let $p_l$ be point farthest from $p$
    • and then let $p_r$ be point farthest from $p_l$
  • once we have $(p_l, p_r)$ we can partition:
    • project all points onto a line $u = p_r - p_l$
    • find the median point $A$ along the line $u$
    • all points on the left of $A$ got to $\text{left}(v)$, on the right of $A$ - to $\text{right}(v)$
    • by using the median we ensure that the depth of the tree is $O(\log N)$ where $N$ is the total number of data points
    • however finding the median is expensive
  • heuristic:
    • can use the mean point as well, i.e. $A = (p_l + p_r) / 2$
  • let $L$ be a $d - 1$ dimensional plane orthogonal to $u$ that goes through $A$
    • this $L$ is a decision boundary - we will use it for querying

After metric tree is constructed at each node we have:

  • the decision boundary $L$
  • a sphere $\mathbb B$ s.t. all points in $N(v)$ are in this sphere
    • let $\text{center}(v)$ be the center of $\mathbb B$ and $r(v)$ be the radius
    • so $N(v) \subseteq \mathbb B\big(\text{center}(v), r(v)\big)$

MT-DFS($q$) - the search algorithm

  • search in a Metric Tree is a guided Depth-First Search
  • the decision boundary $L$ at each node $n$ is used to decide whether to go left or right
    • if $q$ is in the left, then go to $\text{left}(v)$, otherwise - to $\text{right}(v)$
    • (or can project the query point to $u$, and then check if $q < A$ or not)
  • all the time we maintain $x$: nearest neighbor found so far
  • let $d = \| x - q \|$ - distance from best $x$ so far to the query
  • we can use $d$ to prune nodes: we can check if a node is good or no point can better than $x$
    • no point is better than $x$ if $\| \text{center}(r) - q \| - r(v) \geqslant d$

This algorithm is very efficient when dimensionality is $\leqslant 30$

  • but slows down when it increases


  • MT often finds the NN very quickly and then spends 95% of the time verifying that this is the true NN
  • can reduce this time with Spill-Trees


A Spill-Tree is a variant of Metric Tree

  • in which children of a node can "spill over" onto each other
  • i.e. $\text{left}(v)$ and $\text{right}(v)$ are no longer required to be disjoint


  • the decision boundary $L$ still goes though $A$
  • but we define two additional separate planes $L_L$ and $L_R$
  • let $\tau$ be the area that both left and right children of $v$ can share
  • $L_L = L - \tau$ and $L_R = L + \tau$
    • $\tau$ is the size of overlap
  • then $\text{left}(v)$ contains all points on the left of $L_R$ and $\text{right}(v)$ contains all the points on the right of $L_L$
  • illustration:
    • 0efd0ed70d0a4d6fb377d0f88b65d101.png

Why allowing overlap?

  • find the answer approximately, not exactly


  • don't backtrack at all - just do a tree descent, not DFS
  • consider a case when $q$ is close to $L$: it's true that the true NN might be on the other side of $L$
  • so by allowing overlap we hope to catch the true NN on the over side
  • and by varying $\tau$ we can reduce the probability of a mistake

Hybrid Spill-Trees

Problems with Spill-Trees: depth varies a lot with $\tau$


  • let $\rho < 1$ be the balance threshold (usually $\rho = 0.7$)
  • Similar to SP-Trees, but
    • if either of $v$'s children contains more than $\rho \cdot | N(v) |$ elements
    • then don't do overlapping nodes - use usual MT split and mark the node as "non-overlapping"
  • this way we still can maintain the logarithmic depth


  • also hybrid of both
  • if non-overlapping: do backtracking
  • if overlapping: don't backtrack

Random Projections: Dimensionality Reduction

Both SP and MT aren't very efficient for $D \geqslant 30$

  • but by Johnson-Lidenstrauss Lemma (see Achlioptas2003) know that
    • we can always embed $N$ points into a subspace with dimensionality $\log N$
    • with little distortion on pair-wise distances.
  • so let's do a very simple embedding: Random Projections
  • pick up a random subspace $S$ and project all data on $S$


  • do Random Projection as a preprocessing step: project all data points on $S$ and build the tree on the low dimensional representation
  • by doing projection we'll lose some accuracy
  • can fix that by doing multiple different random projections and do a hybrid search for each resulting tree separately
  • if probability of failing to find the true NN is $\delta$, then do doing $L$ different projections we reduce this probability to $\delta^L$


  • Uhlmann, Jeffrey K. "Metric trees." 1991. [1]
  • Omohundro, Stephen M. "Bumptrees for efficient function, constraint, and classification learning." 1991. [2]
  • Achlioptas, Dimitris. "Database-friendly random projections: Johnson-Lindenstrauss with binary coins." 2003. [3]


  • Liu, Ting, et al. "An investigation of practical approximate nearest neighbor algorithms." 2004. [4]